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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
The equation of the circle whose center is at (3, 7) and whose radius is 6 is
Solution:
The equation of the circle is
(x - h)2 + (y - k)2 = r2
Where (h, k) is the center
r is the radius
It is given that
(h, k) = (3, 7)
r = 6
Substituting these values
(x - 3)2 + (y - 7)2 = 62
Expanding using the formula
(a - b)2 = a2 + b2 - 2ab
x2 + 9 - 6x + y2 + 49 - 14y = 36
By further calculation
x2 + y2 - 6x - 14y + 9 + 49 = 36
x2 + y2 - 6x - 14y + 22 = 0
Therefore, the equation of the circle is x2 + y2 - 6x - 14y + 22 = 0.
The equation of the circle whose center is at (3, 7) and whose radius is 6 is
Summary:
The equation of the circle whose center is at (3, 7) and whose radius is 6 is x2 + y2 - 6x - 14y + 22 = 0.
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