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A day full of math games & activities. Find one near you.
The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t2 . Then the maximum (in m) height attained by the object is?
Solution:
It is given that,
Height h in meters of an object varies with time 't' in seconds as h = 10t - 5t2
dh/dt = 10 - 10t
d2h/dt2 = - 10 < 0
Only maxima
dh/dt = 0
t = 1 sec.
hmax = 10(1) - 5(1)2
hmax = 5 meter.
Therefore, the maximum (in m) height attained by the object is 5 meter.
The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t2 . Then the maximum (in m) height attained by the object is?
Summary:
The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t2. Then the maximum (in m) height attained by the object is 5 meter.
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