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# The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t^{2} . Then the maximum (in m) height attained by the object is?

**Solution:**

It is given that,

Height h in meters of an object varies with time 't' in seconds as h = 10t - 5t^{2}

dh/dt = 10 - 10t

d^{2}h/dt^{2} = - 10 < 0

Only maxima

dh/dt = 0

t = 1 sec.

h_{max} = 10(1) - 5(1)^{2}

h_{max }= 5 meter.

Therefore, the maximum (in m) height attained by the object is 5 meter.

## The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t^{2} . Then the maximum (in m) height attained by the object is?

**Summary:**

The height h in meters of an object varies with time 't' in seconds as h = 10t - 5t^{2}. Then the maximum (in m) height attained by the object is 5 meter.

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