The point (6, 5) lies on a circle centered at (3, -2). Find the radius of the circle.
Solution:
The standard form of the equation of a circle is given by
(x - a)2 + (y - b)2 = r2
Where a and b are the coordinates of the center
r is the radius
Given, center = (3, -2) and (x, y) = (6,5)
Substituting the values in standard form of equation we get,
(6 - 3)2 + (5 - (-2))2 = r2
(3)2 + (7)2 = r2
r2 = 9 + 49
r = √58
Therefore, the radius of the circle is √58.
The point (6, 5) lies on a circle centered at (3, -2). Find the radius of the circle.
Summary:
The point (6, 5) lies on a circle centered at (3, -2). The radius of the circle is √58.
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