# The point (6, 5) lies on a circle centered at (3, -2). Find the radius of the circle.

**Solution:**

The standard form of the equation of a circle is given by

(x - a)^{2} + (y - b)^{2} = r^{2}

Where a and b are the coordinates of the center

r is the radius

Given, center = (3, -2) and (x, y) = (6,5)

Substituting the values in standard form of equation we get,

(6 - 3)^{2} + (5 - (-2))^{2 }= r^{2}

(3)^{2} + (7)^{2} = r^{2}

r^{2} = 9 + 49

r = √58

Therefore, the radius of the circle is √58.

## The point (6, 5) lies on a circle centered at (3, -2). Find the radius of the circle.

**Summary:**

The point (6, 5) lies on a circle centered at (3, -2). The radius of the circle is √58.

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