Let's find the number by applying the given conditions in the question as follows

Hence, the original number is 10x + y (Assuming x to be the ten's digit and y to be the one's digit)

After reversing the digits the new number will be 10y + x (After reversing, y becomes the ten's digit and x becomes the one's digit)

Condition 1: Sum of the original number and number obtained by reversing it = 165

Original number + New number = 165

By substituting the values we get,

(10x+y)+(10y+x) = 165 ------------ (1)

Condition 2: The digits of the original number differs by 3

x - y = 3 ---------------- (2) (since, it's given that ten's digit > one's digit)

From equation (1)

11x + 11y = 165

Dividing by 11 on both the sides we get,

x + y = 15 --------------- (3)

By adding equation (2) and (3) we get,

x - y + x + y = 3 + 15

⇒ 2x = 18

⇒ x = 9

⇒ y = 15 - 9 = 6

Hence the original number is 10x + y = 10(9) + 6 = 96

Verification:

We can verify the result by substituting the values in the given conditions:

96 + 69 = 165

9 - 6 = 3

Hence, both the conditions are satisfied.

### Thus, the required number satisfying the given conditions is 96