Three boys step off together from the same spot their steps measure 63 cm, 70 cm, and 77 cm respectively. What is the minimum distance each should cover so that all can cover the distance in complete steps?

We have to find the minimum distance the boys have walked such that they are together.

Answer: 6930 cm

We will find the least common multiple (LCM) of 63, 70 and 77

Explanation:

Distance covered by them will be greater than 63, 70 and 77

Minimum Distance each should cover so that all can cover the distance in complete steps = LCM (63, 70, 77)

Let us find the LCM of 63, 70 and 77

Prime factorization of 63 = 3 × 3 × 7

Prime factorization of  70 = 2 × 5 × 7

Prime factorization of  77 = 7 × 11

LCM (63, 70, 77) = 3 × 3 × 7 × 2 × 5 × 11 = 6930

Therefore, if three boys step off together from the same spot their steps measure 63 cm 70 cm, and 77 cm respectively, minimum Distance each should cover so that all can cover the distance in complete steps is 6930 cm