What are the possible rational zeros of f(x) = x4 + 2x3 - 3x2 - 4x + 18?
Solution:
It is given that
f(x) = x4 + 2x3 - 3x2 - 4x + 18
We have to determine all the possible roots of the given function
From the rational root theorem test
We should factor the leading coefficient and constant term
In the given equation
Leading coefficient = 1
Constant term = 18
Factors of 18 (p) = 1, 2, 3, 6, 9, 18
Factor of 1 (q) = 1
Let us divide each factor of 18 by each factor of 1
The possible root is ± p/q
So the rational roots are - ±1, ±2, ±3, ±6, ±9, ±18.
Therefore, the possible rational zeros are ±1, ±2, ±3, ±6, ±9, ±18.
What are the possible rational zeros of f(x) = x4 + 2x3 - 3x2 - 4x + 18?
Summary:
The possible rational zeros of f(x) = x4 + 2x3 - 3x2 - 4x + 18 are ±1, ±2, ±3, ±6, ±9, ±18.
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