A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
What are the zeros of the quadratic function f(x) = 8x2 - 16x - 15?
Solution:
Given, f(x) = 8x2 - 16x - 15
We have to find zero of the quadratic function.
By using quadratic formula,
\(x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\)
Here, a = 8, b = -16, c = -15
\(x=\frac{-(-16)\pm \sqrt{(-16)^{2}-4(8)(-15)}}{2(8)}\)
\(x=\frac{16\pm \sqrt{256+480}}{16}\)
\(x=\frac{16\pm \sqrt{736}}{16}\)
\(x=\frac{16\pm27.13}{16}\)
Now, \(x=\frac{16+27.13}{16}=\frac{43.13}{16}=2.69\)
\(x=\frac{16-27.13}{16}=\frac{-11.13}{16}=-0.69\)
Therefore, the zeros of the quadratic function are 2.69 and -0.69.
What are the zeros of the quadratic function f(x) = 8x2 - 16x - 15?
Summary:
x = -0.69 and x = 2.69 are zeros of the quadratic function f(x) = 8x2 - 16x - 15.
Math worksheets and
visual curriculum
visual curriculum