What is h(x) = -3x² - 6x + 5 written in vertex form?

Solution:

Given, h(x) = -3x² - 6x + 5,

Using completing the square method

h(x) = -3{x² +2x - 5/3} ,

Now adding and subtracting “Half of coefficient of x” which is 1² we get

h(x) = -3{x² + 2x + 1 - 1 - 5/3}

h(x) = -3{(x + 1)² - 8/3}

h(x)= -3(x + 1)² + 8

This is the required vertex form and the vertex is (-1, 8)

What is h(x) = -3x² - 6x + 5 written in vertex form?

Summary:

The vertex form of h(x) = -3x² - 6x + 5 is -3(x + 1)² + 8