# What is the distance between 1 + 3i and 2 – 4i in the complex plane?

We will use the distance formula concept in order to find the distance.

## Answer: The distance between 1 + 3i and 2 – 4i in the complex plane is **√**50 units

Let us see how we will use the concept of the distance formula in order to find the distance.

**Explanation**:

For the complex vector 1 + 3i it can be written as (1, 3) on the coordinate plane.

Also for the complex vector 2 – 4i it can be written as (2, -4) on the coordinate plane.

Now according to the distance formula, the distance between two points (a, b) and (c, d) in the coordinate plane will be given as.

D = **√**(a - c)^{2} + (b - d)^{2}

Now substituting (1, 3) and (2, -4) in the distance formula we get that.

D = **√**(1 - 2)^{2} + (-4 - 3)^{2}

D = √(-1)^{2} + (-7)^{2}

D = √(1+49)

D = **√**50