What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

Solution:

The formula for the nth term of a geometric progression is

a_n = a₁.r^{n - 1}

Given: First term a₁ = 1 and

Common ratio r = 3

Substituting the values in the formula

a₇ = 1.(3)^{7 - 1}

a₇ = (3)⁶

a₇ = 729

Therefore, the seventh term of a sequence is 729.

What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

Summary:

The seventh term of a sequence whose first term is 1 and whose common ratio is 3 is 729.