# What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

**Solution:**

The formula for the nth term of a geometric progression is

a_{n} = a_{1}.r^{n - 1}

Given: First term a_{1} = 1 and

Common ratio r = 3

Substituting the values in the formula

a_{7} = 1.(3)^{7 - 1}

a_{7} = (3)^{6}

a_{7} = 729

Therefore, the seventh term of a sequence is 729.

## What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

**Summary:**

The seventh term of a sequence whose first term is 1 and whose common ratio is 3 is 729.

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