What is the sum of the geometric sequence 1, 3, 9, ... if there are 10 terms?
Solution:
The formula to find the sum of geometric sequence is
a(rn - 1)/ (r - 1)
Where a is the first number
and r is the common ratio
n is the number of terms
It is given that
a = 1
r = 3/1 = 3
n = 10
Substituting it in the formula:
Sum of the geometric sequence = a(rn - 1)/ (r - 1)
= 1 (310 - 1)/ (3 - 1)
By further calculation, we get
= 1 (59049 - 1)/ 2
= 59048/ 2
So we get
= 29524
Therefore, the sum of the geometric sequence is 29524.
What is the sum of the geometric sequence 1, 3, 9, ... if there are 10 terms?
Summary:
The sum of the geometric sequence 1, 3, 9, ... if there are 10 terms is 29524.
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