What is the sum of the infinite geometric series? -3, -3/2, -3/4, -3/8, -3/16

Solution:

The given geometric series has :

First term = a = -3

The common ratio r = (-3/2)/(-3) = 1/2

The sum of a infinite geometric series is given by:

S = a/(1 - r) (since r < 0)

S = -3/(1 - 1/2)

S = -3/(1/2)

S = -6

What is the sum of the infinite geometric series? -3, -3/2, -3/4, -3/8, -3/16

Summary:

The sum of the infinite geometric series is -6.