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# What is the value of i^{97} - i?

**Solution:**

We know that

i^{2} = √-1 × √-1

= √(-1 × -1)

= 1(1)

i^{97} - i

= i^{96}i - i

= (i^{2})^{48} . i - i

From (1) we know i^{2} = 1,

Therefore

= (1)^{48}.i - i

= 1.i - i

= i - i

= 0

## What is the value of i^{97} - i?

**Summary:**

The value of i^{97} - i is zero.

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