What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 12x + 5?

Solution:

y = 3x² + 12x + 5 [Given]

Standard equation of a parabola in vertex form is

f (x) = ax² + bx + c

The vertex of the parabola is given by (h,k)

X-coordinate of the vertex is x = -b/2a

Comparing the given equation with the standard form

a = 3, b = 12 and c = 5

So we get

x = -12/2(3) = - 2

Substituting the value of x is f (x)

f(-2) = 3(-2)² + 12 (-2) + 5

= 3(4) - 24 + 5

= 12 - 24 + 5

= 17 - 24

= -7

Therefore, the x-coordinate of the vertex of the parabola is (-2,-7)

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What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 12x + 5?

Summary:

The x-coordinate of the vertex of the parabola whose equation is y = 3x² + 12x + 5 is (-2,-7)