Which functions have an axis of symmetry of x = -2? Check all that apply.
f(x) = x² + 4x + 3
f(x) = x² - 4x - 5
f(x) = x² + 6x + 2
f(x) = -2x² - 8x + 1
f(x) = -2x² + 8x - 2 

Solution:

It is given that

Axis of symmetry x = -2

The formula to find the axis of symmetry is x = -b/2a

1) f(x) = x² + 4x + 3

Here a = 1, b = 4, c = 3

x = -4/2 (1) = -4/2 = -2

2) f(x) = x² - 4x - 5

Here a = 1, b = -4, c = -5

x = - (-4)/ 2 (1) = 4/2 = 2

3) f(x) = x² + 6x + 2

Here a = 1, b = 6, c = 2

x = -6/2(1) = -6/2 = -3

4) f(x) = -2x² - 8x + 1

Here a = -2, b = -8, c = 1

x = -(-8)/ 2(-2) = 8/-4 = -2

5) f(x) = -2x² + 8x - 2

Here a = -2, b = 8, c = -2

x = -8/2 (-2) = -8/-4 = 2

Therefore, f(x) = x² + 4x + 3 and f(x) = -2x² - 8x + 1 have an axis of symmetry of x = -2.

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Which functions have an axis of symmetry of x = -2? Check all that apply.

Summary:

The functions f(x) = x² + 4x + 3 and f(x) = -2x² - 8x + 1 have an axis of symmetry of x = -2.