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What is the solution set of x^{2} + 8x + 12 = 0?

An equation in the form of ax^{2} + bx + c = 0 is called as a quadratic equation.

## Answer: The solution set of the following equation x² + 8x + 12 = 0 is -2 and -6

Let's find the values of x

**Explanation:**

We know that the standard form of a quadratic equation is given by,

ax^{2} + bx + c = 0

We have x^{2} + 8x + 12 = 0,

- the coefficient of x
^{2 }= 1 - the coefficient of x = 8
- constant term = 12

Thus, by splitting the middle term,

⇒ x^{2} + 2x + 6x + 12 = 0

⇒ x(x + 2) + 6(x + 2) = 0

⇒ (x + 2) (x + 6) = 0

⇒ x = -2 or -6