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# A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹4000, then find the CP of the scooter.

**Solution:**

Given, a person wanted to sell a scooter at a loss of 25%

But the person sold the scooter at a loss of 20%

The difference between two SP is ₹4000

We have to find the CP of the scooter.

We know, Loss = CP - SP

Let the CP of the scooter be x.

When the shopkeeper sells the scooter at 25% loss,

SP = x - 25% of x

= x - (25/100)x

= 75x/100

When the shopkeeper sells the scooter at 20% loss,

SP = x - 20% of x

= x - (20/100)x

= 80x/100

According to the question,

80x/100 - 75x/100 = 4000

x/100 (80 - 75) = 4000

x/100 (5) = 4000

x/100 = 4000/5

x/100 = 800

x = 800(100)

x = 80000

Therefore, the cost price of the scooter is ₹80,000.

**✦ Try This: **A person wanted to sell a car at a loss of 35%. But at the last moment he changed his mind and sold the car at a loss of 10%. If the difference in the two SP’s is ₹80000, then find the CP of the car.

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 8

**NCERT Exemplar Class 7 Maths Chapter 7 Problem 111**

## A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹4000, then find the CP of the scooter.

**Summary:**

A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹4000, then the CP of the scooter is ₹80,000.

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