# A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.

**Solution:**

Given, the length and width of a school playground are 120 m and 80 m.

The playground is divided by a 2 m wide path parallel to the width of the ground.

The playground is divided by a 3 m wide path parallel to the length of the ground.

We have to find the remaining area of the playground.

Area of rectangle = length × width

Considering school playground,

Length = 120 m

Width = 80 m

__Area__ = 120(80)

= 9600 m²

Considering 2 m wide path parallel to the width of the ground,

Length = 80 - 3 = 77 m

Width = 2 m

Area = 77(2)

= 154 m²

Considering 3 m wide path parallel to the length of the ground,

Length = 120 m

Width = 3 m

Area = 120(3)

= 360 m²

Area of path = 154 + 360

= 514 m²

Remaining area of the playground = area of playground - area of path

= 9600 - 514

= 9086 m²

Therefore, the remaining area of the playground is 9086 m².

**✦ Try This: **If the difference between the circumference and diameter of a circle is 30 cm then what is the radius of the circle?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 115**

## A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.

**Summary:**

A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, the area of the remaining playground is 9086 m².

**☛ Related Questions:**

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