# AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is

a. 5

b. 3

c. √34

d. 4

**Solution:**

It is given that

AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0)

Length of diagonal AB is the distance between the points (0,3) and (5,0)

We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

\(Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

Distance between the points (0,3) and (5,0) can be found by

\(Distance=\sqrt{(5-0)^{2}+(0 - 3)^{2}}\)

So we get

Distance between the points = √(25 + 9) = √34

Distance between the points = √34 units

Therefore, the length of its diagonal is √34 units.

**✦ Try This: **PORS is a rectangle whose three vertices are vertices P (0, 2), O (0, 0) and R (4, 0). The length of its diagonal is

**☛ Also Check: **NCERT Solutions for Class 10 Maths Chapter 7

**NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 5**

## AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is a. 5, b. 3, c. **√**34, d. 4

**Summary:**

AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is √34 units

**☛ Related Questions:**

- The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is a. 5, b. 12, c. 11, d. 7+ √5
- The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is a. 14, b. 28, c. 8, d. 6
- The points (–4, 0), (4, 0), (0, 3) are the vertices of a a. right triangle, b. isosceles triangle, c . . . .

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