# Check whether p(x) is a multiple of g(x) or not : p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2

**Solution:**

Given, p(x) = x³ - 5x² + 4x - 3

Also, g(x) = x - 2

We have to check whether p(x) is a multiple of g(x) or not.

We know that if p(x) is a multiple of g(x) then g(x) must be divisible by p(x)

Let g(x) = 0

x - 2 = 0

x = 2

Put x = 2 in p(x)

p(2) = (2)³ - 5(2)² + 4(2) - 3

= 8 - 5(4) + 8 - 3

= 8 - 20 + 5

= 13 - 20

= -7

p(x) ≠ 0

Since the __remainder__ is not zero, g(x) is not divisible by p(x)

Therefore, p(x) is not a multiple of g(x).

**✦ Try This: **Check whether p(x) is a multiple of g(x) or not, where p(x) = 3x³ + 3x + 9, g(x) = x - 3

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 15(i)**

## Check whether p(x) is a multiple of g(x) or not : p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2

**Summary:**

p(x) is not a multiple of g(x) or not, where p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2 since p(x) ≠ 0 when x = 2

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