# Define a relation R on the set N of natural numbers by

R = {(x, y) : y = x + 5, x is a natural number less than 4; x, y ∈ N}

Depict this relationship using roster form. Write down the domain and the range

**Solution:**

R = {(x, y) : y = x + 5, x is a natural number less than 4; x, y ∈ N}

The natural numbers less than 4 are 1, 2, and 3.

Therefore, R = {(1, 6), (2, 7), (3, 8)}

The domain of R is the set of all first elements of the ordered pairs in the relation.

Hence, Domain of R = {1, 2, 3}.

The range of R is the set of all second elements of the ordered pairs in the relation.

Therefore, Range of R = {6, 7, 8}

NCERT Solutions Class 11 Maths Chapter 2 Exercise 2.2 Question 2

## Define a relation R on the set N of natural numbers by R = {(x, y) : y = x + 5, x is a natural number less than 4; x, y ∈ N}. Depict this relationship using roster form. Write down the domain and the range

**Summary:**

R = {(x, y) : y = x + 5, x is a natural number less than 4; x, y ∈ N} is given. We have found that range of R = {6, 7, 8} and Co-domain of R = {1, 2, 3}