# Determine the following polynomials has x - 2 a factor : 3x² + 6x - 24

**Solution:**

Given, the __polynomial__ is p(x) = 3x² + 6x - 24

We have to determine if x - 2 is a __factor__ of p(x).

Given, g(x) = x - 2

Let g(x) = 0

x - 2 = 0

x = 2

Substitute x = 2 in p(x),

p(2) = 3(2)² + 6(2) - 24

= 3(4) + 12 - 24

= 12 + 12 - 24

= 24 - 24

= 0

p(2) = 0

Since p(x) = 0 when x = 2, x - 2 is the factor of p(x)

Therefore, x - 2 is the factor of 3x² + 6x - 24.

**✦ Try This: **Determine the following polynomials has x - 1 a factor : 3x² + 9x - 12

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 17(i)**

## Determine the following polynomials has x - 2 a factor : 3x² + 6x - 24

**Summary:**

A polynomial is a type of expression in which the exponents of all variables should be a whole number. The polynomial 3x² + 6x - 24 has a factor x - 2 as p(x) = 0 when x = 2

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