# Draw the graphs for the following tables of values, with suitable scales on the axes.

(a) Cost of apples

(b)Distance travelled by a car

(i) How much distance did the car cover during the period 7.30 a.m.to 8 a.m.?

(ii) What was the time when the car had covered a distance of 100 km since its start?

(c) Interest on deposits for a year:

(i) Does the graph pass through the origin?

(ii) Use the graph to find the interest on Rs 2500 for a year:

To get an interest of Rs 280 per year, how much money should be deposited?

**Solution:**

Reasoning:

(a) Considering ‘Number of apples’ on the horizontal axis and ‘Cost (in Rs)’ on the vertical axis starting from origin i.e. (0,0) and find the value of ‘Cost’ on the vertical axis according to the given value of ‘Number of apples’ on the horizontal axis value or vice versa.

(b) Considering ‘Time (in hours)’ on the horizontal axis and ‘Distance (in km)’ on the vertical axis starting from origin i.e. (0,0) and find the value of ‘Distance’ on the vertical axis according to the given value of ‘Time’ on the horizontal axis value or vice versa.

(c) Considering ‘Deposit (in Rs)’ on the horizontal axis and ‘Simple interest (in Rs)’ on the vertical axis starting from origin i.e. (0,0) and find the value of ‘Simple interest’ on the vertical axis according to the given value of ‘Deposit’ on the horizontal axis value or vice versa.

Steps:

(a) Taking a suitable scale:

For x-axis, 2 unit = 1 apple and for y-axis, 2 unit = Rs 5.

We can mark the number of apples on the x-axis and the cost of apples on the y-axis. A graph of the given data is as follows.

(b) Taking a suitable scale

For x-axis, 4 units = 1 hour and for y-axis, 2 units = 20 km,

We can represent the time on the x-axis and the distance covered by the car on the y-axis. A graph of the given data is as follows.

(i) During the period 7:30 am to 8 am, the car covered a distance of 20 km.

(ii) The car covered a distance of 100 km at 7:30 am since its start.

(c) Taking a suitable scale,

For x-axis, 2 unit = Rs 1000 and for y-axis, 2 unit = Rs 50

We can represent the deposit on the x-axis and the interest earned on that deposit on the y-axis. A graph of the given data is obtained as follows.

From the graph, the following points can be observed.

(i) The graph passes through the origin.

(ii) The interest earned in a year on a deposit of Rs 2500 is Rs 200.

(iii) To get an interest of Rs 280 per year, Rs 3500 should be deposited.

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 15

**Video Solution:**

## Draw the graphs for the following tables of values, with suitable scales on the axes.(a) Cost of applesCost of apples(b)Distance travelled by a carDistance travelled by a car(i) How much distance did the car cover during the period 7.30 a.m.to 8 a.m.?(ii) What was the time when the car had covered a distance of 100 km since its start?(c) Interest on deposits for a year:Interest on deposits for a year:(i) Does the graph pass through the origin?(ii) Use the graph to find the interest on Rs 2500 for a year:To get an interest of Rs 280 per year, how much money should be deposited?

Class 8 Maths NCERT Solutions Chapter 15 Exercise 15.3 Question 1

**Summary:**

From the given data, the graphs are plotted for the following tables of values, with suitable scales on the axes

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