# Evaluate the following limits in Exercises 1 to 22: limₓ→₀ (( x + 1)⁵ - 1)/x

**Solution:**

The given limit is, limₓ→₀ ((x + 1)^{5} - 1)/x

By direct substitution of x = 0 gives 0/0 which is an indeterminate form. So we have to find this limit differently.

Put x + 1 = y , so that x = y - 1

Accordingly,

limₓ→₀ ((x + 1)^{5} - 1)/x = limᵧ→₀ (y)^{5} - 1)/(y - 1)

= 5 × (1)^{5 - 1} [∵ limₓ→₀ (x^{n} - a^{n})/(x - a) = na^{n - 1}]

= 5

Hence,

limₓ→₀ (( x + 1)^{5} - 1)/x = 5

NCERT Solutions Class 11 Maths Chapter 13 Exercise 13.1 Question 6

## Evaluate the following limits in Exercises 1 to 22: limₓ→₀ (( x + 1)⁵ - 1)/x

**Summary:**

The value of the limit limₓ→₀ (( x + 1)^{5} - 1)/x is 5

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