# Find the equation of the circle with centre (1, 1) and radius √2

**Solution:**

The equation of a circle with centre(h, k) and radius r is given as

(x - h)^{2} + (y - k)^{2} = r^{2}

It is given that centre (h, k) = (1, 1)

and radius (r ) = √2.

Therefore, the equation of the circle is

(x - 1)^{2} + (y - 1)^{2} = (√2)^{2}

x^{2} - 2x + 1 + y^{2} - 2y + 1 = 2

x^{2} + y^{2} - 2x - 2y = 0

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.1 Question 4

## Find the equation of the circle with centre (1, 1) and radius √2.

**Summary:**

The equation of the circle is x^{2} + y^{2} - 2x - 2y = 0