# Find the equation of the circle with centre (- a, - b) and radius √a² + b²

**Solution:**

The equation of a circle with centre(h, k) and radius r is given as

(x - h)^{2} + (y - k)^{2} = r^{2}

It is given that centre (h, k) = (- a, - b)

and radius (r ) = √a² + b².

Therefore, the equation of the circle is

(x - a)^{2} + (y - b)^{2} = (√a² + b²)^{2}

x^{2} + 2ax + a^{2} + y^{2} + 2by + b^{2} = a^{2} - b^{2}

x^{2} + y^{2} + 2ax + 2by + 2b^{2} = 0

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.1 Question 5

## Find the equation of the circle with centre (- a, - b) and radius √a² + b²

**Summary:**

The equation of the circle is x^{2} + y^{2} + 2ax + 2by + 2b^{2} = 0

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