# Find the equation of the hyperbola satisfying the given conditions: Vertices (± 2, 0) , Foci (± 3, 0)

**Solution:**

Vertices (± 2, 0), Foci (± 3, 0)

Here, the vertices are on the ix-axis.

Therefore,

the equation of the hyperbola is of the form x^{2}/a^{2} - y^{2}/b^{2} = 1

Since the vertices are (± 2, 0), a = 2

Since the foci are (± 3, 0), c = 3

We know that, c^{2} = a^{2} + b^{2}

Hence,

⇒ 2^{2} + b^{2} = 3^{2}

⇒ b^{2} = 9 - 4

⇒ b^{2} = 5

Thus, the equation of the hyperbola is x^{2}/4 - y^{2}/5 = 1

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.4 Question 7

## Find the equation of the hyperbola satisfying the given conditions: Vertices (± 2, 0) , Foci (± 3, 0)

**Summary:**

The equation of the hyperbola is x^{2}/4 - y^{2}/5 = 1 while Vertices are (± 2, 0) and Foci are (± 3, 0)