# Find the principal value of cos^{-1} (√3/2)

**Solution:**

Inverse trigonometric functions are the inverse ratio of the basic trigonometric ratios

Here the basic trigonometric function of Sin θ = y can be changed to

θ = sin^{-1} y

Let,

cos^{-1} (√3/2) = y

Hence,

cos y = (√3/2)

= cos (π / 6)

The range of the principal value of cos^{-}^{1} (x) is (0, π).

Thus,

the principal value of cos^{-1} (√3/2)

= π / 6

NCERT Solutions for Class 12 Maths - Chapter 2 Exercise 2.1 Question 2

## Find the principal value of cos^{-1} (√3/2)

**Summary:**

The principal value of cos^{-1} (√3/2) = π / 6. The range of the principal value of cos^{-}^{1} (x) is (0, π)