from a handpicked tutor in LIVE 1-to-1 classes

# Horse stable is in the form of a cuboid, whose external dimensions are 70 m × 35 m × 40 m, surrounded by a cylinder halved vertically through diameter 35 m and it is open from one rectangular face 70 m × 40 m. Find the cost of painting the exterior of the stable at the rate of Rs 2/m²

**Solution:**

The horse stable as described above can be represented by the schematic diagram below:

The area which needs to be painted is as follows:

Area to be painted = Back Wall of the stable (1) + Side Walls (2 & 6) of stable + Curved surface of cylindrical roof (5) + Side walls of cylindrical roof(3 & 4)

Let

the radius of the cylindrical roof = r

Height of the cuboid part of the stable = H

Breadth of the stable = b

Length of the stable = l

We know from the diagram above:

r = 35/2 m

H = 40 m

b = 35 m

l = 70m

Area to be painted = l × h + b × h + b × h + (½)(2πrl) + (½)(πr²) + (½)(πr²)

Basically there are six surfaces to be painted:

Area = 70 × 40 + 35 × 40 + 35 × 40 + (½)(2 × 22/7 × 35/2 × 70) + (½)(22/7 × 35/2 × 35/2) +

(½)(22/7 × 35/2 × 35/2)

= 2800 + 1400 + 1400 + 3850 + 1925/4 + 1925/4

= 5600 + 3850 + 962.5

= 5600 + 4812.5

= 10412.5m²

Cost of painting the surface = Rs..2/m²

Total Cost of Painting = 10412.5 × 2 = Rs. 20,825

**✦ Try This: **Horse stable is in the form of a cuboid, whose external dimensions are 35 m × 28 m × 35 m, surrounded by a cylinder halved vertically through diameter 28 m and it is open from one rectangular face 35 m × 35 m. Find the cost of painting the exterior of the stable at the rate of Rs 3/m²

The horse stable as described above can be represented by the schematic diagram below:

The area which needs to painted is as follows:

Area to be painted = Back Wall of the stable (1) + Side Walls (2 & 6) of stable + Curved surface of cylindrical roof (5) + Side walls of cylindrical roof(3 & 4)

Let

radius of the cylindrical roof = r

Height of the cuboid part of the stable = H

Breadth of the stable = b

Length of the stable = l

We know from the diagram above:

r = 28/2 m = 14m

H = 35 m

b = 28 m

l = 35m

Area to be painted = l × h + b × h + b × h + (½)(2πrl) + (½)(πr²) + (½)(πr²)

Basically there are six surfaces to be painted:

Area = 35 × 35 + 28 × 35 + 28 × 35 + (½)(2 × 22/7 × 28/2 × 35) + (½)(22/7 × 28/2 × 28/2) +

(½)(22/7 × 28/2 × 28/2)

= 1225 + 980 + 980+ 1540+ 308+ 308

= 1225 + 1960+ 1540 + 616

= 1225+ 4116

= 5341m²

Cost of painting the surface = Rs..3/m²

Total Cost of Painting = 5341 × 3 = Rs. 16023

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 11

**NCERT Exemplar Class 8 Maths Chapter 11 Sample Problem 11**

## The parallel sides of a trapezium are 40 cm and 20 cm. If its non-parallel sides are both equal, each being 26 cm, find the area of the trapezium

**Summary:**

Horse stable is in the form of a cuboid, whose external dimensions are 70 m × 35 m × 40 m, surrounded by a cylinder halved vertically through diameter 35 m and it is open from one rectangular face 70 m × 40 m. The cost of painting the exterior of the stable at the rate of Rs 2/m² is Rs. 20,825

**☛ Related Questions:**

- A cube of side 5 cm is painted on all its faces. If it is sliced into 1 cubic centimetre cubes, how . . . .
- A cube of side 4 cm is cut into 1 cm cubes. What is the ratio of the surface areas of the original c . . . .
- A circle of maximum possible size is cut from a square sheet of board. Subsequently, a square of max . . . .

visual curriculum