from a handpicked tutor in LIVE 1-to-1 classes

# If AB = QR, BC = PR and CA = PQ, then

a. ∆ ABC ≅ ∆ PQR

b. ∆ CBA ≅ ∆ PRQ

c. ∆ BAC ≅ ∆ RPQ

d. ∆ PQR ≅ ∆ BCA

**Solution:**

In ∆ ABC and ∆ PQR

It is given that

AB = QR

BC = PR

CA = PQ

From the SSS criterion

SSS or Side-Side-Side congruence rule states that if three sides of one triangle are equal to three corresponding sides of another triangle, then the triangles are congruent.

∆ CBA ≅ ∆ PRQ

Therefore, if AB = QR, BC = PR and CA = PQ, then ∆ CBA ≅ ∆ PRQ.

**✦ Try This: **If PQ = YZ, QR = XZ and RP = XY, then a. ∆ PQR ≅ ∆ XYZ, b. ∆ RQP ≅ ∆ XZY, c. ∆ QPR ≅ ∆ ZXY, d. ∆ XYZ ≅ ∆ RQP

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 7

**NCERT Exemplar Class 9 Maths Exercise 7.1 Problem 2**

## If AB = QR, BC = PR and CA = PQ, then a. ∆ ABC ≅ ∆ PQR , b. ∆ CBA ≅ ∆ PRQ , c. ∆ BAC ≅ ∆ RPQ , d. ∆ PQR ≅ ∆ BCA

**Summary:**

SSS congruence rule states that if three sides of one triangle are equal to three corresponding sides of another triangle, then the triangles are congruent. If AB = QR, BC = PR and CA = PQ, then ∆ CBA ≅ ∆ PRQ

**☛ Related Questions:**

visual curriculum