In a certain lottery 10,000 tickets are sold, and ten equal prizes are awarded. What is the probability of not getting a prize if you buy  (a) one ticket  (b) two tickets  (c) 10 tickets.

Solution:

The total number of tickets sold = 10000

The number of prizes awarded = 10.

Number of tickets not awarded = 10000 - 10 = 9990

(a) The required probability is,

P (not getting a prize) = ⁹⁹⁹⁰C₁/¹⁰⁰⁰⁰C₁ = 9990 / 10000 = 999/1000
 

(b) Number of tickets not awarded = 10000 - 10 = 9990

If we buy two tickets, then the required probability is,

P (not getting a prize) = ⁹⁹⁹⁰C₂/¹⁰⁰⁰⁰C₂ 
 

(c) If we buy ten tickets, then the required probability is,

P (not getting a prize) = ⁹⁹⁹⁰C₁₀/¹⁰⁰⁰⁰C₁₀

NCERT Solutions Class 11 Maths Chapter 16 Exercise ME Question 4

In a certain lottery 10,000 tickets are sold, and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets.

Summary:

The probability of not getting a prize if you buy (a) one ticket is 999/1000 (b) two tickets ⁹⁹⁹⁰C₂/¹⁰⁰⁰⁰C₂  (c) 10tickets is ⁹⁹⁹⁰C₁₀/¹⁰⁰⁰⁰C₁₀