# In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is :

a. 6

b. 7

c. 8

d. 12

**Solution:**

Consider x and y as the upper and lower class limit in a frequency distribution.

It is given that

Mid value of a class=10

(x + y)/2 = 10

x + y = 20 …. (1)

Width of a class=6

x - y = 6 …. (2)

By adding both the equations

2x = 20 + 6

2x = 26

Dividing both sides by 2

x = 13

Substitute x value in equation (1)

13 + y = 20

By further calculation

y = 20 - 13

y = 7

Therefore, the lower limit of the class is 7.

**✦ Try This: **In a frequency distribution, the mid value of a class is 12 and the width of the class is 8. The lower limit of the class is :

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.1 Problem 3**

## In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is : a. 6, b. 7, c. 8, d. 12

**Summary:**

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is 7

**☛ Related Questions:**

- The width of each of five continuous classes in a frequency distribution is 5 and the lower class-li . . . .
- Let m be the mid-point and l be the upper class limit of a class in a continuous frequency distribut . . . .
- The class marks of a frequency distribution are given as follows : 15, 20, 25, ...The class correspo . . . .

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