# The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is:

a. 15

b. 25

c. 35

d. 40

**Solution:**

Consider x and y as the upper and lower limit of the frequency distribution

It is given that

Width of the class=5

x - y = 5 …. (1)

Lowest class y = 10

Substituting it in equation (1)

x - 10 = 5

x = 5 + 10

x = 15

So the upper class limit of lowest class is 15

Upper class limit of highest class=Number of continuous classes x class width + lower class limit of lowest class

Substituting the values

= 5 x 5 + 10

= 25 + 10

= 35

Therefore, the upper class-limit of the highest class is 35.

**✦ Try This: **The width of each of five continuous classes in a frequency distribution is 6 and the lower class-limit of the lowest class is 12. The upper class-limit of the highest class is:

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.1 Problem 4**

## The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is: a. 15, b. 25, c. 35, d. 40

**Summary:**

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is 35

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