Learn Ncert All Solutions

from a handpicked tutor in LIVE 1-to-1 classes

from a handpicked tutor in LIVE 1-to-1 classes

# In the formula x̄ = a + h f_{i} u_{i}/ f_{i}, for finding the mean of grouped frequency distribution, u_{i} =

a. x_{i} + a /h

b. h(x_{i} - a)

c. x_{i} - a /h

d. a - x_{i} /h

**Solution:**

From the question

x = a + h (f_{i}u_{i}/f_{i})

It is the step deviation formula

Where

x_{i} = data values

a = assumed mean

h = class size

When the class size is similar, the calculation of mean can be simplified by using the coded mean of u_{1}, u_{2}, u_{3} …..

Where u_{i} = (x_{i} - a)/h

Therefore, for finding the mean of grouped frequency distribution, u_{i} = (x_{i} - a)/h.

**✦ Try This: **If u_{i} = (x_{i} - 25)/10, Σf_{i}u_{i} = 50 and Σf_{i} = 100 then \(\overline{x}\) is equal to

**☛ Also Check: **NCERT Solutions for Class 10 Maths Chapter 14

**NCERT Exemplar Class 10 Maths Exercise 13.1**** Problem 4**

## In the formula x̄ = a + h f_{i} u_{i}/ f_{i}, for finding the mean of grouped frequency distribution, u_{i} = a. x_{i} + a /h, b. h(x_{i} - a), c. x_{i} - a /h, d. a - x_{i} /h

**Summary:**

In the formula x̄ = a + h f_{i}u_{i}/f_{i}, for finding the mean of grouped frequency distribution, u_{i} = (x_{i }- a)/h

**☛ Related Questions:**

- The abscissa of the point of intersection of the less than type and of the more than type cumulative . . . .
- For the following distribution: Class 0-5 5-10 10-15 15-20 20-25 Frequency 10 15 12 20 9 the sum of . . . .
- Consider the following frequency distribution: Class 0-5 6-11 12-17 18-23 24-29 Frequency 13 1 . . . .

Math worksheets and

visual curriculum

visual curriculum