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# Interest on ₹12500 at 18% per annum for a period of 2 years and 4 months is ________. Fill in the blanks to make the statement true.

**Solution:**

Interest on ₹12500 at 18% per annum for a period of 2 years and 4 months is ________.

We have to fill in the blanks to make the statement true.

According to the question,

P = ₹12500

R = 18%

T = 2 years and 4 months = 2 + 4/12

= 2 + 1/3

= 7/3 years

We know, __Interest__, I = P × R × T/100

= 12500 × 18 × 7/100 × 3

= 12500 × 6 × 7/100

= 125 × 6 × 7

= ₹5250

Therefore, the interest is ₹5250.

**✦ Try This: **Interest on ₹500 at 5% per annum for a period of 3 years and 8 months is ________. Fill in the blanks to make the statement true.

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 8

**NCERT Exemplar Class 7 Maths Chapter 7 Problem 49**

## Interest on ₹12500 at 18% per annum for a period of 2 years and 4 months is ________. Fill in the blanks to make the statement true

**Summary:**

Interest on ₹12500 at 18% per annum for a period of 2 years and 4 months is ₹5250.

**☛ Related Questions:**

- 25 ml is _________ percent of 5 litres. Fill in the blanks to make the statement true
- If A is increased by 20%, it equals B. If B is decreased by 50%, it equals C. Then __________ % of A . . . .
- Interest = P×R×T/100 , where T is ____________ R% is ____________ and P is ____________. Fill in the . . . .

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