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# Length of tape required to cover the edges of a semicircular disc of radius 10 cm is

(a) 62.8 cm

(b) 51.4 cm

(c) 31.4 cm

(d) 15.7 cm

**Solution:**

Given, a semicircular disc of radius 10 cm

We have to find the length of tape required to cover the edges of a semicircular disc.

Perimeter of semicircle = circumference of semicircle + diameter

Circumference of semicircle = πr

Where, r is the radius of circle

= 22/7 × 10

= 22(10)/7

= 220/7

= 31.4 cm

Perimeter of semicircle = 31.4 + 10(2)

= 31.4 + 20

= 51.4 cm

Therefore, the perimeter of semicircle is 51.4 cm

**✦ Try This: **Length of tape required to cover the edges of a semicircular disc of radius 8 cm is

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 21**

## Length of tape required to cover the edges of a semicircular disc of radius 10 cm is (a) 62.8 cm, (b) 51.4 cm, (c) 31.4 cm, (d) 15.7 cm

**Summary:**

Length of tape required to cover the edges of a semicircular disc of radius 10 cm is 51.4 cm

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