# Match column I to column II in the following:

Column I Column II

(i) a/b ÷ a/b (a) -a/b

(ii) a/b ÷ c/d (b) -1

(iii) a/b ÷ (-1) (c) 1

(iv) a/b ÷ -a/b (d) bc/ad

(v) b/a ÷ (d/c) (e) ad/bc

**Solution:**

We have to match Column I to column II

Considering (a/b) ÷ (a/b),

(a/b) ÷ (a/b) = (a/b) × (b/a)

= (a × b) / (b × a)

= 1

Considering (a/b) ÷ (c/d),

(a/b) ÷ (c/d) = (a/b) × (d/c)

= (a × d) / (b × c)

= ad/bc

Considering (a/b) ÷ (-1),

(a/b) ÷ (-1) = (a/b) × 1/(-1)

= (a × 1) / b × (-1)

= a/-b

= -a/b

Considering (a/b) ÷ (-a/b),

(a/b) ÷ (a/b) = (a/b) × (b/-a)

= (a × b) / (b × (-a))

= 1/-1

= -1

Considering (b/a) ÷ (d/c),

(b/a) ÷ (d/c) = (b/a) × (c/d)

= (b × c) / (a × d)

= bc/ad

Therefore, (a/b) ÷ (a/b) = 1

(a/b) ÷ (c/d) = ad/bc

(a/b) ÷ (-1) = -a/b

(a/b) ÷ (-a/b) = -1

(b/a) ÷ (d/c) = bc/ad

**✦ Try This: **Find the value of 11 3/4 × 12 5/6

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 9

**NCERT Exemplar Class 7 Maths Chapter 8 Problem 66**

## Match column I to column II in the following: Column I Column II (i) a/b ÷ a/b (a) -a/b (ii) a/b ÷ c/d (b) -1 (iii) a/b ÷ (-1) (c) 1 (iv) a/b ÷ -a/b (d) bc/ad (v) b/a ÷ (d/c) (e) ad/bc

**Summary:**

On matching column I to column II, (i) → (c), (ii) → (e), (iii) → (a), (iv) → (b), (v) → (d)

**☛ Related Questions:**

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