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# Prove that: 3) cot²π/6 + cosec 5π/6 + 3tan²π/6 = 6

**Solution:**

We know that:

cos π/6 = √3, cosec 5π/6 = 2 and tan π/6 = 1/√3 (by trigonometric table).

Substituting these values in the LHS,

LHS = cot^{2}π/6 + cosec 5π/6 + 3tan^{2}π/6 = 6

= (√3)^{2 }+ 2 + 3 × (1/√3)^{2}

= 3 + 2 + [3 × (1/3)]

= 3 + 2 + 1

= 6

= RHS

NCERT Solutions Class 11 Maths Chapter 3 Exercise 3.3 Question 3

## Prove that: 3) cot²π/6 + cosec 5π/6 + 3tan²π/6 = 6

**Summary:**

We got, cot^{2}π/6 + cosec 5π/6 + 3tan^{2}π/6 = 6. Hence Proved.

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