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# Solve each of the equation in Exercises 6 to 9: 21x² – 28x + 10 = 0

**Solution:**

The given quadratic equation can be written as,

21x² – 28x + 10 = 0

By comparing this with ax^{2} + bx + c = 0, we get a = 21, b = -28, and c = 10.

Its discriminant is, D = b^{2} - 4ac = (-28)^{2} - 4(21)(10) = -56

The solutions of the given quadratic equation are,

(- b ± √D)/2a = 28 ± √(-56) ) / 2(21)

= (28 ± i√56) / 42 [∵ √- 1 = i]

= (28 ± 2i√14) / 42

= 2/3 ± (√14/21) i

Hene the solutions of the given equation are x = 2/3 + i√14/ 21, 2/3 - i√ 14 / 21

NCERT Solutions Class 11 Maths Chapter 5 Exercise ME Question 9

## Solve each of the equation in Exercises 6 to 9: 21x² – 28x + 10 = 0

**Summary:**

The solutions of 21x² – 28x + 10 = 0 are x = 2/3 + i√14 / 21, 2/3 - i√ 14/ 21

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