# Solve each of the equation in Exercises 6 to 9: 3x² – 4x + 20/3 = 0

**Solution:**

The given quadratic equation can be written as,

9x^{2} - 12x + 20 = 0

By comparing this with ax^{2} + bx + c = 0, we get a = 9, b = -12, and c = 20.

Its discriminant is, D = b^{2} - 4ac = (-12)^{2} - 4(9)(20) = -576

The solutions of the given quadratic equation are,

(- b ± √D)/2a = (12 ± √(-576) ) / 2(9)

= (12 ± i√576) / 18 [∵ √- 1 = i]

= (12 ± 24i) / 18

= 2/3 ± (4/3) i

Hence, the solutions of 3x^{2} – 4x + 20/3 = 0 are x = 2/3 + 4/3 i, 2/3 - 4/3 i

NCERT Solutions Class 11 Maths Chapter 5 Exercise ME Question 6

## Solve each of the equation in Exercises 6 to 9: 3x² – 4x + 20/3 = 0

**Summary:**

The solutions of 3x^{2} – 4x + 20/3 = 0 are x = 2/3 + 4/3 i, 2/3 - 4/3 i

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