# Solve each of the equation in Exercises 6 to 9: x² – 2x + 3/2 = 0

**Solution:**

he given quadratic equation can be written as,

2x^{2} - 4x + 3 = 0

By comparing this with ax^{2} + bx + c = 0, we get a = 2, b = -4, and c = 3.

Its discriminant is, D = b^{2} - 4ac = (-4)^{2} - 4(2)(3) = -8

The solutions of the given quadratic equation are,

(- b ± √D)/2a = (4 ± √(-8) ) / 2(2)

= (4 ± i√8) / 4 [∵ √- 1 = i]

= (4 ± 2i√2) / 4

= 1 ± (√2/2) i

Hence the solutions of the the quadratic equation are x^{2} – 2x + 3/2 = 0, x = x = 1 + √ 2i / 2, 1 - √ 2i / 2

NCERT Solutions Class 11 Maths Chapter 5 Exercise ME Question 7

## Solve each of the equation in Exercises 6 to 9: x² – 2x + 3/2 = 0

**Summary:**

The solutions of the the quadratic equation are x^{2} – 2x + 3/2 = 0, x = x = 1 + √ 2i / 2, 1 - √ 2i / 2.