Solve the given inequality for real x : 37 - (3x + 5) ≥ 9x - 8(x - 3)

Solution:

37 - (3x + 5) ≥ 9x - 8(x - 3)

⇒ 37 - 3x - 5 ≥ 9x - 8x + 24

⇒ 32 - 3x ≥ x + 24

⇒ 32 - 24 ≥ x + 3x

⇒ 8 ≥ 4x

⇒ x ≤ 2

Thus, all real numbers x,

which are less than or equal to 2, are the solutions of the given inequality.

Hence, the solution set of the given inequality is (- ∞, 2]

NCERT Solutions Class 11 Maths Chapter 6 Exercise 6.1 Question 14

Solve the given inequality for real x : 37 - (3x + 5) ≥ 9x - 8(x - 3)

Summary:

A linear inequation 37 - (3x + 5) ≥ 9x - 8(x - 3) is given. We have found that the solution set of the given inequality is (- ∞, 2]