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# The value of (3x³ + 9x² + 27x) ÷ 3x is

(a) x² + 9 + 27x

(b) 3x³ + 3x² + 27x

(c) 3x³ + 9x² + 9

(d) x² + 3x + 9

**Solution:**

Correct option is (d).

Given, (3x³ + 9x² + 27x) ÷ 3x

3x is the common term in the expression of the numerator.

∴ 3x(x² + 3x + 9) ÷ 3x

Canceling common terms,

3x(x² + 3x + 9) ÷ 3x = x² + 3x + 9

**✦ Try This: **The value of (4x³ + 36x² + 28x) ÷ 2x is (a) 2x² - 18x - 14, (b) 2x² + 18x - 14, (c) 2x² - 18x + 14, (d) 2x² + 18x + 14

Option (d)

(4x³ + 36x² + 28x) ÷ 2x

2x (2x² + 18x + 14) ÷ 2x

2x² + 18x + 14

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 9

**NCERT Exemplar Class 8 Maths Chapter 7 Problem 31**

## The value of (3x³ + 9x² + 27x) ÷ 3x is (a) x² + 9 + 27x, (b) 3x³ + 3x² + 27x, (c) 3x³ + 9x² + 9, (d) x² + 3x + 9

**Summary:**

The value of (3x³ + 9x² + 27x) ÷ 3x is x² + 3x + 9

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