There are four containers that are arranged in the ascending order of their heights. If the height of the smallest container given in the figure is expressed as 7/25 x = 10.5 cm. Find the height of the largest container.
Solution:
It is given that
Height of the smallest container = 10.5 cm
We know that
7/25 x = 10.5 cm
It can be written as
x = 10.5 ÷ 7/25
x = 105/10 ÷ 7/25
So we get
x = 105/10 × 25/7
x = (15 × 25)/ 10
x = 375/10
x = 37.5 cm
Therefore, the height of the largest container is 37.5 cm.
✦ Try This: There are four containers that are arranged in the ascending order of their heights. If the height of the smallest container given in the figure is expressed as 8/4 x = 12.5 cm. Find the height of the largest container.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 2
NCERT Exemplar Class 7 Maths Chapter 2 Exercise Problem 118
There are four containers that are arranged in the ascending order of their heights. If the height of the smallest container given in the figure is expressed as 7/25 x = 10.5 cm. Find the height of the largest container.
Summary:
There are four containers that are arranged in the ascending order of their heights. If the height of the smallest container given in the figure is expressed as 7/25 x = 10.5 cm. The height of the largest container is 37.5 cm
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