# Write the first five terms of the sequences whose nth term is a_{n} = n (n^{2} + 5)/4

**Solution:**

nth term is given as: a_{n} = n (n^{2} + 5)/4

Substituting n = 1, 2, 3, 4, 5

a_{1} = 1 (1^{2} + 5)/4 = 3/2

a_{2} = 2 (2^{2} + 5)/4 = 9/2

a_{3} = 3 (3^{2} + 5)/4 = 21/2

a_{4} = 4 (4^{2} + 5)/4 = 21

a_{5} = 5 (5^{2} + 5)/4 = 75/2

Therefore, the required terms are 3/2, 9/2, 21/2, 21, 75/2

NCERT Solutions Class 11 Maths Chapter 9 Exercise 9.1 Question 6

## Write the first five terms of the sequences whose nth term is a_{n} = n (n^{2} + 5)/4

**Summary:**

The question tells us that the nth term is a_{n} = n (n^{2} + 5)/4. Therefore the terms are 3/2, 9/2, 21/2, 21, 75/2

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