Write the general term in the expansion of (x² - y)⁶

Solution:

It is known that (r + 1)^th term, (Tᵣ ₊ ₁) in the binomial expansion of (a + b)ⁿ is given by Tᵣ ₊ ₁ = ⁿCᵣ aⁿ ⁻ ʳ bʳ.

Thus, the general term in the expansion of (x² - y)⁶ is

Tᵣ ₊ ₁ = ⁶Cᵣ(x²)⁶ ⁻ ʳ (- y)ʳ

= (- 1)ʳ ⁶Cᵣ (x)¹²⁻²ʳ (y)ʳ

NCERT Solutions Class 11 Maths Chapter 8 Exercise 8.2 Question 3

Write the general term in the expansion of (x² - y)⁶

Summary:

Using binomial theorem, the general term in the expansion of (x² - y)⁶ is to be found. We have found that it is equal to (- 1)ʳ ⁶Cᵣ (x)¹²⁻²ʳ (y)ʳ