# Write the numbers given in the following place value table in decimal form:

**Solution:**

The decimal values for the numbers in the given table is:

**(a)**

= (0 x 100) + (0 x 10) + (3 x 1) + (2 x 1/10) + (5 x 1/100) + (0 x 1/1000)

= 0 + 0 + 3 + 2/10 + 5/100 + 0

= 3 + 0.2 + 0.05 = 3.25

**(b)**

= (1 x 100) + (0 x 10) + (2 x 1) + (6 x 1/10) + (3 x 1/100) + (0 x 1/1000)

= 100 + 0 + 2 + 6/10 + 3/100 + 0

= 102 + 0.6 + 0.03 = 102.63

**(c)**

= (0 x 100) + (3 x 10) + (0 x 1) + (0 x 1/10) + (2 x 1/100) + (5 x 1/1000)

= 0 + 30 + 0 + 0 + 0.02 + 0.005

= 30.025

**(d)**

= 2 x 100 + 1 x 10 + 1 x 1 + 9 x 1/10 + 0 x 1/100 + 2 x 1/100

= 200 + 10 + 1 + 0.9 + 0.00 + 0.002

= 211 + 0.902 = 211.902

**(e)**

= 0 x 100 + 1 x 10 + 2 x 1 + 2 x 1/10 + 4 x 1/100 + 1 x 1/1000

= 0 + 10 + 2 + 2/10 + 4/100 + 1/1000

= 12 + 0.2 + 0.04 + 0.001 = 12.241

NCERT Solutions for Class 6 Maths Chapter 2 Exercise 8.2 Question 2

## Write the numbers given in the following place value table in decimal form:

**Summary:**

The decimal values for the numbers in the given table are (a) 3.25 (b) 102.63 (c) 30.025 (d) 211.902 (e) 12.241

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