# A bag contains 25 paise coins, 50 paise coins and 1 rupee coins whose values are in the ratio of 8:4:2. The total values of coins are 840. Then, find the total number of coins.

The problem can be solved using linear equations in one variable.

## Answer: The total number of coins is 1960.

Let's understand the terms in detail.

## Explanation:

Given that the number of 25p, 50p and Rs.1 coins are in the ratio 8 : 4 : 2

So, let the number of 25p coins be 8x, 50p coins be 4x, Rs.1 coins be 2x.

Number of coins | Contributed Value | ||

25 paise | 8x | 25(8x) | 200x |

50 paise | 4x | 50(4x) | 200x |

Rs 1 = 100 paise | 2x | 100(2x) | 200x |

Total | 14x | 600x |

⇒ Total amount = 600x = Rs 840 = 84000 paise

⇒ 600x = 84000

⇒ x = 84000/600

⇒ x = 140

So, total number of coins = 8x + 4x + 2x = 14x = 14(140) = 1960.