An acute angle θ is in a right triangle with sinθ = 6/7. What is the value of cotθ?

Solution:

Given sinθ = 6/7

θ = sin^-1(6/7)

θ = 59°

cot θ = cot 59°

Given θ in a right triangle.

So using trigonometric ratios,

cot θ = cos59°/ sin59° 

= 0.51/0.85

cotθ = 0.60

An acute angle θ is in a right triangle with sinθ = 6/7. What is the value of cotθ?

Summary:

An acute angle θ is in a right triangle with sinθ = 6/7. The value of cotθ is 0.60.