# An acute angle θ is in a right triangle with sinθ = 6/7. What is the value of cotθ?

**Solution:**

Given sinθ = 6/7

θ = sin^{-1}(6/7)

θ = 59°

cot θ = cot 59°

Given θ in a right triangle.

So using trigonometric ratios,

cot θ = cos59°/ sin59°

= 0.51/0.85

cotθ = 0.60

## An acute angle θ is in a right triangle with sinθ = 6/7. What is the value of cotθ?

**Summary:**

An acute angle θ is in a right triangle with sinθ = 6/7. The value of cotθ is 0.60.

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