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# At which root does the graph of f(x) = (x + 4)^{6}(x + 7)^{5} cross the x axis?

**Solution:**

If f(x) = (x + 4)^{6 }(x + 7)^{5} cross the x-axis,

then y = f(x) = 0.

If f(x) = 0,

then (x + 4)^{6}(x + 7)^{5} = 0.

If (x + 4)^{6}(x + 7)^{5} = 0,

then x + 4 = 0 and x + 7 = 0

⇒ x = - 4 and x = - 7

**Therefore, the roots at which the graph of f(x) = (x + 4) ^{6}(x + 7)^{5} cross the x axis are -4 and -7.**

## At which root does the graph of f(x) = (x + 4)^{6}(x + 7)^{5 }cross the x axis?

**Summary:**

f(x) = (x + 4)^{6}(x + 7)^{5} cross the x axis are -4 and -7. The root at which a curve crosses the y axis can be found by equating x = f(y) = 0. Because on x-axis y coordinate is zero and on y-axis x coordinate is zero.

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